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8=2x+2/3x
We move all terms to the left:
8-(2x+2/3x)=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-(+2x+2/3x)+8=0
We get rid of parentheses
-2x-2/3x+8=0
We multiply all the terms by the denominator
-2x*3x+8*3x-2=0
Wy multiply elements
-6x^2+24x-2=0
a = -6; b = 24; c = -2;
Δ = b2-4ac
Δ = 242-4·(-6)·(-2)
Δ = 528
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{528}=\sqrt{16*33}=\sqrt{16}*\sqrt{33}=4\sqrt{33}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-4\sqrt{33}}{2*-6}=\frac{-24-4\sqrt{33}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+4\sqrt{33}}{2*-6}=\frac{-24+4\sqrt{33}}{-12} $
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