8=3(b-8)-(-2)

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Solution for 8=3(b-8)-(-2) equation: 



8=3(b-8)-(-2)

We move all terms to the left:

8-(3(b-8)-(-2))=0



We calculate terms in parentheses: -(3(b-8)-(-2)), so:

3(b-8)-(-2)

We add all the numbers together, and all the variables

3(b-8)+2

We multiply parentheses

3b-24+2

We add all the numbers together, and all the variables

3b-22

Back to the equation:

-(3b-22)



We get rid of parentheses

-3b+22+8=0

We add all the numbers together, and all the variables

-3b+30=0

We move all terms containing b to the left, all other terms to the right

-3b=-30

b=-30/-3

b=+10

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