8=3(x+2)-2(x+1)

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Solution for 8=3(x+2)-2(x+1) equation: 



8=3(x+2)-2(x+1)

We move all terms to the left:

8-(3(x+2)-2(x+1))=0



We calculate terms in parentheses: -(3(x+2)-2(x+1)), so:

3(x+2)-2(x+1)

We multiply parentheses

3x-2x+6-2

We add all the numbers together, and all the variables

x+4

Back to the equation:

-(x+4)



We get rid of parentheses

-x-4+8=0

We add all the numbers together, and all the variables

-1x+4=0

We move all terms containing x to the left, all other terms to the right

-x=-4

x=-4/-1

x=+4

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