8=3(y-2)+4y

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Solution for 8=3(y-2)+4y equation: 



8=3(y-2)+4y

We move all terms to the left:

8-(3(y-2)+4y)=0



We calculate terms in parentheses: -(3(y-2)+4y), so:

3(y-2)+4y

We add all the numbers together, and all the variables

4y+3(y-2)

We multiply parentheses

4y+3y-6

We add all the numbers together, and all the variables

7y-6

Back to the equation:

-(7y-6)



We get rid of parentheses

-7y+6+8=0

We add all the numbers together, and all the variables

-7y+14=0

We move all terms containing y to the left, all other terms to the right

-7y=-14

y=-14/-7

y=+2

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