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8=3/4(10z+16)
We move all terms to the left:
8-(3/4(10z+16))=0
Domain of the equation: 4(10z+16))!=0We multiply all the terms by the denominator
z∈R
-(3+8*4(10z+16))=0
We calculate terms in parentheses: -(3+8*4(10z+16)), so:We add all the numbers together, and all the variables
3+8*4(10z+16)
determiningTheFunctionDomain 8*4(10z+16)+3
Wy multiply elements
32z(1+3
Back to the equation:
-(32z(1+3)
-(32z4=0
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