8=4(x-3)-(x-8)

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Solution for 8=4(x-3)-(x-8) equation:



8=4(x-3)-(x-8)
We move all terms to the left:
8-(4(x-3)-(x-8))=0
We calculate terms in parentheses: -(4(x-3)-(x-8)), so:
4(x-3)-(x-8)
We multiply parentheses
4x-(x-8)-12
We get rid of parentheses
4x-x+8-12
We add all the numbers together, and all the variables
3x-4
Back to the equation:
-(3x-4)
We get rid of parentheses
-3x+4+8=0
We add all the numbers together, and all the variables
-3x+12=0
We move all terms containing x to the left, all other terms to the right
-3x=-12
x=-12/-3
x=+4

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