8=4(x-3)-(x-8)

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Solution for 8=4(x-3)-(x-8) equation: 



8=4(x-3)-(x-8)

We move all terms to the left:

8-(4(x-3)-(x-8))=0



We calculate terms in parentheses: -(4(x-3)-(x-8)), so:

4(x-3)-(x-8)

We multiply parentheses

4x-(x-8)-12

We get rid of parentheses

4x-x+8-12

We add all the numbers together, and all the variables

3x-4

Back to the equation:

-(3x-4)



We get rid of parentheses

-3x+4+8=0

We add all the numbers together, and all the variables

-3x+12=0

We move all terms containing x to the left, all other terms to the right

-3x=-12

x=-12/-3

x=+4

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