8=4+(20/2x)

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Solution for 8=4+(20/2x) equation: 



8=4+(20/2x)

We move all terms to the left:

8-(4+(20/2x))=0



Domain of the equation: 2x))!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-(4+(+20/2x))+8=0

We multiply all the terms by the denominator


-(4+(+20+8*2x))=0



We calculate terms in parentheses: -(4+(+20+8*2x)), so:

4+(+20+8*2x)

determiningTheFunctionDomain
(+20+8*2x)+4

We add all the numbers together, and all the variables

(8*2x+20)+4

We get rid of parentheses

8*2x+20+4

We add all the numbers together, and all the variables

8*2x+24

Wy multiply elements

16x+24

Back to the equation:

-(16x+24)



We get rid of parentheses

-16x-24=0

We move all terms containing x to the left, all other terms to the right

-16x=24

x=24/-16

x=-1+1/2

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