8=4+15(b-5)

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Solution for 8=4+15(b-5) equation: 



8=4+15(b-5)

We move all terms to the left:

8-(4+15(b-5))=0



We calculate terms in parentheses: -(4+15(b-5)), so:

4+15(b-5)

determiningTheFunctionDomain
15(b-5)+4

We multiply parentheses

15b-75+4

We add all the numbers together, and all the variables

15b-71

Back to the equation:

-(15b-71)



We get rid of parentheses

-15b+71+8=0

We add all the numbers together, and all the variables

-15b+79=0

We move all terms containing b to the left, all other terms to the right

-15b=-79

b=-79/-15

b=5+4/15

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