8=4-(q-2)+4

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Solution for 8=4-(q-2)+4 equation: 



8=4-(q-2)+4

We move all terms to the left:

8-(4-(q-2)+4)=0



We calculate terms in parentheses: -(4-(q-2)+4), so:

4-(q-2)+4

determiningTheFunctionDomain
-(q-2)+4+4

We add all the numbers together, and all the variables

-(q-2)+8

We get rid of parentheses

-q+2+8

We add all the numbers together, and all the variables

-1q+10

Back to the equation:

-(-1q+10)



We get rid of parentheses

1q-10+8=0

We add all the numbers together, and all the variables

q-2=0

We move all terms containing q to the left, all other terms to the right

q=2

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