8=40/2y-3

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Solution for 8=40/2y-3 equation:



8=40/2y-3
We move all terms to the left:
8-(40/2y-3)=0
Domain of the equation: 2y-3)!=0
y∈R
We get rid of parentheses
-40/2y+3+8=0
We multiply all the terms by the denominator
3*2y+8*2y-40=0
Wy multiply elements
6y+16y-40=0
We add all the numbers together, and all the variables
22y-40=0
We move all terms containing y to the left, all other terms to the right
22y=40
y=40/22
y=1+9/11

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