8=7(y+1)+2y

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Solution for 8=7(y+1)+2y equation: 



8=7(y+1)+2y

We move all terms to the left:

8-(7(y+1)+2y)=0



We calculate terms in parentheses: -(7(y+1)+2y), so:

7(y+1)+2y

We add all the numbers together, and all the variables

2y+7(y+1)

We multiply parentheses

2y+7y+7

We add all the numbers together, and all the variables

9y+7

Back to the equation:

-(9y+7)



We get rid of parentheses

-9y-7+8=0

We add all the numbers together, and all the variables

-9y+1=0

We move all terms containing y to the left, all other terms to the right

-9y=-1

y=-1/-9

y=1/9

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