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8=c-3/4c+12+4
We move all terms to the left:
8-(c-3/4c+12+4)=0
Domain of the equation: 4c+12+4)!=0We add all the numbers together, and all the variables
We move all terms containing c to the left, all other terms to the right
4c+4)!=-12
c∈R
-(c-3/4c+16)+8=0
We get rid of parentheses
-c+3/4c-16+8=0
We multiply all the terms by the denominator
-c*4c-16*4c+8*4c+3=0
Wy multiply elements
-4c^2-64c+32c+3=0
We add all the numbers together, and all the variables
-4c^2-32c+3=0
a = -4; b = -32; c = +3;
Δ = b2-4ac
Δ = -322-4·(-4)·3
Δ = 1072
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1072}=\sqrt{16*67}=\sqrt{16}*\sqrt{67}=4\sqrt{67}$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-4\sqrt{67}}{2*-4}=\frac{32-4\sqrt{67}}{-8} $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+4\sqrt{67}}{2*-4}=\frac{32+4\sqrt{67}}{-8} $
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