8=k2/11

Solution for 8=k2/11 equation:

8=k2/11

We move all terms to the left:

8-(k2/11)=0

We add all the numbers together, and all the variables

-(+k2/11)+8=0

We get rid of parentheses

-k2/11+8=0

We multiply all the terms by the denominator


-k2+8*11=0

We add all the numbers together, and all the variables

-1k^2+88=0

a = -1; b = 0; c = +88;
Δ = b2-4ac
Δ = 02-4·(-1)·88
Δ = 352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{352}=\sqrt{16*22}=\sqrt{16}*\sqrt{22}=4\sqrt{22}$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{22}}{2*-1}=\frac{0-4\sqrt{22}}{-2}
=-\frac{4\sqrt{22}}{-2}
=-\frac{2\sqrt{22}}{-1}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{22}}{2*-1}=\frac{0+4\sqrt{22}}{-2}
=\frac{4\sqrt{22}}{-2}
=\frac{2\sqrt{22}}{-1}
$