8a-20/4=4(2a-5)/4=2a-5

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Solution for 8a-20/4=4(2a-5)/4=2a-5 equation: 



8a-20/4=4(2a-5)/4=2a-5

We move all terms to the left:

8a-20/4-(4(2a-5)/4)=0

We add all the numbers together, and all the variables

8a-(4(2a-5)/4)-5=0

We multiply all the terms by the denominator


8a*4)-(4(2a-5)-5*4)=0

We add all the numbers together, and all the variables

8a*4)-(4(2a-5)=0

Wy multiply elements

32a^2=0

a = 32; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·32·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{0}{64}=0$

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