8a-5(a+1)=8-2(a-3)

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Solution for 8a-5(a+1)=8-2(a-3) equation: 



8a-5(a+1)=8-2(a-3)

We move all terms to the left:

8a-5(a+1)-(8-2(a-3))=0

We multiply parentheses

8a-5a-(8-2(a-3))-5=0



We calculate terms in parentheses: -(8-2(a-3)), so:

8-2(a-3)

determiningTheFunctionDomain
-2(a-3)+8

We multiply parentheses

-2a+6+8

We add all the numbers together, and all the variables

-2a+14

Back to the equation:

-(-2a+14)



We add all the numbers together, and all the variables

3a-(-2a+14)-5=0

We get rid of parentheses

3a+2a-14-5=0

We add all the numbers together, and all the variables

5a-19=0

We move all terms containing a to the left, all other terms to the right

5a=19

a=19/5

a=3+4/5

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