8a2=12+a

Solution for 8a2=12+a equation:

8a^2=12+a

We move all terms to the left:

8a^2-(12+a)=0

We add all the numbers together, and all the variables

8a^2-(a+12)=0

We get rid of parentheses

8a^2-a-12=0

We add all the numbers together, and all the variables

8a^2-1a-12=0

a = 8; b = -1; c = -12;
Δ = b2-4ac
Δ = -12-4·8·(-12)
Δ = 385
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{385}}{2*8}=\frac{1-\sqrt{385}}{16}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{385}}{2*8}=\frac{1+\sqrt{385}}{16}
$