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8a^2=12+a
We move all terms to the left:
8a^2-(12+a)=0
We add all the numbers together, and all the variables
8a^2-(a+12)=0
We get rid of parentheses
8a^2-a-12=0
We add all the numbers together, and all the variables
8a^2-1a-12=0
a = 8; b = -1; c = -12;
Δ = b2-4ac
Δ = -12-4·8·(-12)
Δ = 385
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{385}}{2*8}=\frac{1-\sqrt{385}}{16} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{385}}{2*8}=\frac{1+\sqrt{385}}{16} $
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