8b+28=64-2b

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Solution for 8b+28=64-2b equation: 



8b+28=64-2b

We move all terms to the left:

8b+28-(64-2b)=0

We add all the numbers together, and all the variables

8b-(-2b+64)+28=0

We get rid of parentheses

8b+2b-64+28=0

We add all the numbers together, and all the variables

10b-36=0

We move all terms containing b to the left, all other terms to the right

10b=36

b=36/10

b=3+3/5

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