8b+3+-10b=2(b-2)+3

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Solution for 8b+3+-10b=2(b-2)+3 equation: 



8b+3+-10b=2(b-2)+3

We move all terms to the left:

8b+3+-10b-(2(b-2)+3)=0

We add all the numbers together, and all the variables

-2b-(2(b-2)+3)=0



We calculate terms in parentheses: -(2(b-2)+3), so:

2(b-2)+3

We multiply parentheses

2b-4+3

We add all the numbers together, and all the variables

2b-1

Back to the equation:

-(2b-1)



We get rid of parentheses

-2b-2b+1=0

We add all the numbers together, and all the variables

-4b+1=0

We move all terms containing b to the left, all other terms to the right

-4b=-1

b=-1/-4

b=1/4

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