8b-1=7(b-7)+7b

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Solution for 8b-1=7(b-7)+7b equation: 



8b-1=7(b-7)+7b

We move all terms to the left:

8b-1-(7(b-7)+7b)=0



We calculate terms in parentheses: -(7(b-7)+7b), so:

7(b-7)+7b

We add all the numbers together, and all the variables

7b+7(b-7)

We multiply parentheses

7b+7b-49

We add all the numbers together, and all the variables

14b-49

Back to the equation:

-(14b-49)



We get rid of parentheses

8b-14b+49-1=0

We add all the numbers together, and all the variables

-6b+48=0

We move all terms containing b to the left, all other terms to the right

-6b=-48

b=-48/-6

b=+8

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