8b-2(b+4)=-6(b-4)-4b

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Solution for 8b-2(b+4)=-6(b-4)-4b equation: 



8b-2(b+4)=-6(b-4)-4b

We move all terms to the left:

8b-2(b+4)-(-6(b-4)-4b)=0

We multiply parentheses

8b-2b-(-6(b-4)-4b)-8=0



We calculate terms in parentheses: -(-6(b-4)-4b), so:

-6(b-4)-4b

We add all the numbers together, and all the variables

-4b-6(b-4)

We multiply parentheses

-4b-6b+24

We add all the numbers together, and all the variables

-10b+24

Back to the equation:

-(-10b+24)



We add all the numbers together, and all the variables

6b-(-10b+24)-8=0

We get rid of parentheses

6b+10b-24-8=0

We add all the numbers together, and all the variables

16b-32=0

We move all terms containing b to the left, all other terms to the right

16b=32

b=32/16

b=2

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