8b-2(b+5)=2(b-1)

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Solution for 8b-2(b+5)=2(b-1) equation: 



8b-2(b+5)=2(b-1)

We move all terms to the left:

8b-2(b+5)-(2(b-1))=0

We multiply parentheses

8b-2b-(2(b-1))-10=0



We calculate terms in parentheses: -(2(b-1)), so:

2(b-1)

We multiply parentheses

2b-2

Back to the equation:

-(2b-2)



We add all the numbers together, and all the variables

6b-(2b-2)-10=0

We get rid of parentheses

6b-2b+2-10=0

We add all the numbers together, and all the variables

4b-8=0

We move all terms containing b to the left, all other terms to the right

4b=8

b=8/4

b=2

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