8b-3=2-(b-4)

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Solution for 8b-3=2-(b-4) equation:



8b-3=2-(b-4)
We move all terms to the left:
8b-3-(2-(b-4))=0
We calculate terms in parentheses: -(2-(b-4)), so:
2-(b-4)
determiningTheFunctionDomain -(b-4)+2
We get rid of parentheses
-b+4+2
We add all the numbers together, and all the variables
-1b+6
Back to the equation:
-(-1b+6)
We get rid of parentheses
8b+1b-6-3=0
We add all the numbers together, and all the variables
9b-9=0
We move all terms containing b to the left, all other terms to the right
9b=9
b=9/9
b=1

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