8b-6(8b+2)=6(b-2)

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Solution for 8b-6(8b+2)=6(b-2) equation: 



8b-6(8b+2)=6(b-2)

We move all terms to the left:

8b-6(8b+2)-(6(b-2))=0

We multiply parentheses

8b-48b-(6(b-2))-12=0



We calculate terms in parentheses: -(6(b-2)), so:

6(b-2)

We multiply parentheses

6b-12

Back to the equation:

-(6b-12)



We add all the numbers together, and all the variables

-40b-(6b-12)-12=0

We get rid of parentheses

-40b-6b+12-12=0

We add all the numbers together, and all the variables

-46b=0

b=0/-46

b=0

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