If it's not what You are looking for type in the equation solver your own equation and let us solve it.
8b^2+10b=0
a = 8; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·8·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*8}=\frac{-20}{16} =-1+1/4 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*8}=\frac{0}{16} =0 $
| (x+4)/5=x+2 | | 64=2l+2(20) | | -0.03x+520.0=460 | | 5(x+10)-6x=x+6 | | 0.67h-0.2=5.8 | | (100/x)*x=(100/18.75)*x | | 12x+20x-9+3=-6x+3-9 | | 1/8y+1/5=9/40 | | 2x-6x+3x-9=1 | | 6x/4=7/3 | | 4(3x-22)=12x-88 | | (3/4)g-9=4(g+1) | | −37−6u=−7 | | 4=a+10/12 | | 5x-89=-12x+115 | | 5(x+2)=4(x+10) | | k-157=1 | | 3x+6=3x+66 | | (3y+4)(3+y)=0 | | 2x+2(5x-6)=72 | | -3(k-5)-(4k-2)=4 | | -34c+7=31 | | -33+x=37+6x | | a=1/2*11*4 | | 5x-27=2x+13 | | 199t-5-3=67.5 | | 2x+7(x-4)=44 | | 9+5x=−1 | | 7x+8=8(x-6 | | 82=(2x-8)+(3x-12)+x | | 3/2b+5=20−b | | 8x=4x+76 |