8b2+11-11=6

Solution for 8b2+11-11=6 equation:

8b^2+11-11=6

We move all terms to the left:

8b^2+11-11-(6)=0

We add all the numbers together, and all the variables

8b^2-6=0

a = 8; b = 0; c = -6;
Δ = b2-4ac
Δ = 02-4·8·(-6)
Δ = 192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{192}=\sqrt{64*3}=\sqrt{64}*\sqrt{3}=8\sqrt{3}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{3}}{2*8}=\frac{0-8\sqrt{3}}{16}
=-\frac{8\sqrt{3}}{16}
=-\frac{\sqrt{3}}{2}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{3}}{2*8}=\frac{0+8\sqrt{3}}{16}
=\frac{8\sqrt{3}}{16}
=\frac{\sqrt{3}}{2}
$