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8b^2+11b-11=6
We move all terms to the left:
8b^2+11b-11-(6)=0
We add all the numbers together, and all the variables
8b^2+11b-17=0
a = 8; b = 11; c = -17;
Δ = b2-4ac
Δ = 112-4·8·(-17)
Δ = 665
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{665}}{2*8}=\frac{-11-\sqrt{665}}{16} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{665}}{2*8}=\frac{-11+\sqrt{665}}{16} $
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