8b2-16b+6=0

Solution for 8b2-16b+6=0 equation:

8b^2-16b+6=0

a = 8; b = -16; c = +6;
Δ = b2-4ac
Δ = -162-4·8·6
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-8}{2*8}=\frac{8}{16}
=1/2
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+8}{2*8}=\frac{24}{16}
=1+1/2
$