8c(-8c-9)=6c(-c+2)

Solution for 8c(-8c-9)=6c(-c+2) equation:

8c(-8c-9)=6c(-c+2)

We move all terms to the left:

8c(-8c-9)-(6c(-c+2))=0

We add all the numbers together, and all the variables

8c(-8c-9)-(6c(-1c+2))=0

We multiply parentheses

-64c^2-72c-(6c(-1c+2))=0


We calculate terms in parentheses: -(6c(-1c+2)), so:

6c(-1c+2)

We multiply parentheses

-6c^2+12c

Back to the equation:

-(-6c^2+12c)


We get rid of parentheses

-64c^2+6c^2-12c-72c=0

We add all the numbers together, and all the variables

-58c^2-84c=0

a = -58; b = -84; c = 0;
Δ = b2-4ac
Δ = -842-4·(-58)·0
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-84)-84}{2*-58}=\frac{0}{-116}
=0
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-84)+84}{2*-58}=\frac{168}{-116}
=-1+13/29
$