8c(c-5)(c+2)=0

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Solution for 8c(c-5)(c+2)=0 equation: 


Simplifying
8c(c + -5)(c + 2) = 0

Reorder the terms:
8c(-5 + c)(c + 2) = 0

Reorder the terms:
8c(-5 + c)(2 + c) = 0

Multiply (-5 + c) * (2 + c)
8c(-5(2 + c) + c(2 + c)) = 0
8c((2 * -5 + c * -5) + c(2 + c)) = 0
8c((-10 + -5c) + c(2 + c)) = 0
8c(-10 + -5c + (2 * c + c * c)) = 0
8c(-10 + -5c + (2c + c2)) = 0

Combine like terms: -5c + 2c = -3c
8c(-10 + -3c + c2) = 0
(-10 * 8c + -3c * 8c + c2 * 8c) = 0
(-80c + -24c2 + 8c3) = 0

Solving
-80c + -24c2 + 8c3 = 0

Solving for variable 'c'.

Factor out the Greatest Common Factor (GCF), '8c'.
8c(-10 + -3c + c2) = 0

Factor a trinomial.
8c((-2 + -1c)(5 + -1c)) = 0

Ignore the factor 8.

Subproblem 1
Set the factor 'c' equal to zero and attempt to solve:

Simplifying
c = 0

Solving
c = 0

Move all terms containing c to the left, all other terms to the right.

Simplifying
c = 0

Subproblem 2
Set the factor '(-2 + -1c)' equal to zero and attempt to solve:

Simplifying
-2 + -1c = 0

Solving
-2 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + -1c = 0 + 2

Combine like terms: -2 + 2 = 0
0 + -1c = 0 + 2
-1c = 0 + 2

Combine like terms: 0 + 2 = 2
-1c = 2

Divide each side by '-1'.
c = -2

Simplifying
c = -2

Subproblem 3
Set the factor '(5 + -1c)' equal to zero and attempt to solve:

Simplifying
5 + -1c = 0

Solving
5 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -1c = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -1c = 0 + -5
-1c = 0 + -5

Combine like terms: 0 + -5 = -5
-1c = -5

Divide each side by '-1'.
c = 5

Simplifying
c = 5
Solution
c = {0, -2, 5}

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