8c+12=4(3+2c)

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Solution for 8c+12=4(3+2c) equation: 



8c+12=4(3+2c)

We move all terms to the left:

8c+12-(4(3+2c))=0

We add all the numbers together, and all the variables

8c-(4(2c+3))+12=0



We calculate terms in parentheses: -(4(2c+3)), so:

4(2c+3)

We multiply parentheses

8c+12

Back to the equation:

-(8c+12)



We get rid of parentheses

8c-8c-12+12=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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