8c-(10-6c)=32

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Solution for 8c-(10-6c)=32 equation: 



8c-(10-6c)=32

We move all terms to the left:

8c-(10-6c)-(32)=0

We add all the numbers together, and all the variables

8c-(-6c+10)-32=0

We get rid of parentheses

8c+6c-10-32=0

We add all the numbers together, and all the variables

14c-42=0

We move all terms containing c to the left, all other terms to the right

14c=42

c=42/14

c=3

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