8c-(c+3)=-(2c+1)-3

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Solution for 8c-(c+3)=-(2c+1)-3 equation:



8c-(c+3)=-(2c+1)-3
We move all terms to the left:
8c-(c+3)-(-(2c+1)-3)=0
We get rid of parentheses
8c-c-(-(2c+1)-3)-3=0
We calculate terms in parentheses: -(-(2c+1)-3), so:
-(2c+1)-3
We get rid of parentheses
-2c-1-3
We add all the numbers together, and all the variables
-2c-4
Back to the equation:
-(-2c-4)
We add all the numbers together, and all the variables
7c-(-2c-4)-3=0
We get rid of parentheses
7c+2c+4-3=0
We add all the numbers together, and all the variables
9c+1=0
We move all terms containing c to the left, all other terms to the right
9c=-1
c=-1/9
c=-1/9

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