8c-3(c+4)=4(c+2(3-c))

Solution for 8c-3(c+4)=4(c+2(3-c)) equation:

Simplifying
8c + -3(c + 4) = 4(c + 2(3 + -1c))

Reorder the terms:
8c + -3(4 + c) = 4(c + 2(3 + -1c))
8c + (4 * -3 + c * -3) = 4(c + 2(3 + -1c))
8c + (-12 + -3c) = 4(c + 2(3 + -1c))

Reorder the terms:
-12 + 8c + -3c = 4(c + 2(3 + -1c))

Combine like terms: 8c + -3c = 5c
-12 + 5c = 4(c + 2(3 + -1c))
-12 + 5c = 4(c + (3 * 2 + -1c * 2))
-12 + 5c = 4(c + (6 + -2c))

Reorder the terms:
-12 + 5c = 4(6 + c + -2c)

Combine like terms: c + -2c = -1c
-12 + 5c = 4(6 + -1c)
-12 + 5c = (6 * 4 + -1c * 4)
-12 + 5c = (24 + -4c)

Solving
-12 + 5c = 24 + -4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '4c' to each side of the equation.
-12 + 5c + 4c = 24 + -4c + 4c

Combine like terms: 5c + 4c = 9c
-12 + 9c = 24 + -4c + 4c

Combine like terms: -4c + 4c = 0
-12 + 9c = 24 + 0
-12 + 9c = 24

Add '12' to each side of the equation.
-12 + 12 + 9c = 24 + 12

Combine like terms: -12 + 12 = 0
0 + 9c = 24 + 12
9c = 24 + 12

Combine like terms: 24 + 12 = 36
9c = 36

Divide each side by '9'.
c = 4

Simplifying
c = 4