8d+2(d+3)=-2(d-2)

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Solution for 8d+2(d+3)=-2(d-2) equation: 



8d+2(d+3)=-2(d-2)

We move all terms to the left:

8d+2(d+3)-(-2(d-2))=0

We multiply parentheses

8d+2d-(-2(d-2))+6=0



We calculate terms in parentheses: -(-2(d-2)), so:

-2(d-2)

We multiply parentheses

-2d+4

Back to the equation:

-(-2d+4)



We add all the numbers together, and all the variables

10d-(-2d+4)+6=0

We get rid of parentheses

10d+2d-4+6=0

We add all the numbers together, and all the variables

12d+2=0

We move all terms containing d to the left, all other terms to the right

12d=-2

d=-2/12

d=-1/6

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