8d-4=2(1+d)

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Solution for 8d-4=2(1+d) equation: 



8d-4=2(1+d)

We move all terms to the left:

8d-4-(2(1+d))=0

We add all the numbers together, and all the variables

8d-(2(d+1))-4=0



We calculate terms in parentheses: -(2(d+1)), so:

2(d+1)

We multiply parentheses

2d+2

Back to the equation:

-(2d+2)



We get rid of parentheses

8d-2d-2-4=0

We add all the numbers together, and all the variables

6d-6=0

We move all terms containing d to the left, all other terms to the right

6d=6

d=6/6

d=1

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