If it's not what You are looking for type in the equation solver your own equation and let us solve it.
8g^2+22g+5=0
a = 8; b = 22; c = +5;
Δ = b2-4ac
Δ = 222-4·8·5
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-18}{2*8}=\frac{-40}{16} =-2+1/2 $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+18}{2*8}=\frac{-4}{16} =-1/4 $
| -9=0.4p | | 1x+16=4x-5 | | x/x+2/3=9/35 | | 4x-7=2(2x-8) | | A2+12a+35=0 | | -4p+22=14 | | 4b+9=33 | | 6−2c=4 | | 3x+5-2x+7=15 | | 1/3(c-7)=1 | | 3=7+u/2 | | f/8-25=-28 | | 53=4w+8 | | -31+-7h=-94 | | 2k-¢=18 | | 5=4g-15 | | 2x-14-5x+11=16-5x | | -3v/7=21 | | x⁴-15x²+44=0 | | g/6+18=25 | | 7n-8-2n=3(n+3)+6n+12 | | 3x*4=100 | | c+15=20 | | 0=5h^2-h-42 | | 108x=180 | | 25x+6-3x+17=32+40x+10 | | 0.5x-8=-0.5x+10 | | 25x+6-3x+17=32+40x+16 | | 25x+6-3x+17=32+40x+15 | | 25x+6-3x+17=32+40x+13 | | 0.5-8=-0.5x+10 | | g/3+2=4 |