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8g^2-58g+99=0
a = 8; b = -58; c = +99;
Δ = b2-4ac
Δ = -582-4·8·99
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-58)-14}{2*8}=\frac{44}{16} =2+3/4 $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-58)+14}{2*8}=\frac{72}{16} =4+1/2 $
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