8h(9h-1)=0

Solution for 8h(9h-1)=0 equation:

8h(9h-1)=0

We multiply parentheses

72h^2-8h=0

a = 72; b = -8; c = 0;
Δ = b2-4ac
Δ = -82-4·72·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8}{2*72}=\frac{0}{144}
=0
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8}{2*72}=\frac{16}{144}
=1/9
$