8i(5-5i)=0

Solution for 8i(5-5i)=0 equation:

8i(5-5i)=0

We add all the numbers together, and all the variables

8i(-5i+5)=0

We multiply parentheses

-40i^2+40i=0

a = -40; b = 40; c = 0;
Δ = b2-4ac
Δ = 402-4·(-40)·0
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-40}{2*-40}=\frac{-80}{-80}
=1
$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+40}{2*-40}=\frac{0}{-80}
=0
$