8k(k=3)=2k-15

Solution for 8k(k=3)=2k-15 equation:

8k(k=3)=2k-15

We move all terms to the left:

8k(k-(3))=0

We multiply parentheses

8k^2-24k=0

a = 8; b = -24; c = 0;
Δ = b2-4ac
Δ = -242-4·8·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-24}{2*8}=\frac{0}{16}
=0
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+24}{2*8}=\frac{48}{16}
=3
$