8k+12=2(k+-3)

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Solution for 8k+12=2(k+-3) equation: 



8k+12=2(k+-3)

We move all terms to the left:

8k+12-(2(k+-3))=0

We add all the numbers together, and all the variables

8k-(2(k-3))+12=0



We calculate terms in parentheses: -(2(k-3)), so:

2(k-3)

We multiply parentheses

2k-6

Back to the equation:

-(2k-6)



We get rid of parentheses

8k-2k+6+12=0

We add all the numbers together, and all the variables

6k+18=0

We move all terms containing k to the left, all other terms to the right

6k=-18

k=-18/6

k=-3

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