8k+3(1-2k)=5-2(2k-5)

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Solution for 8k+3(1-2k)=5-2(2k-5) equation: 



8k+3(1-2k)=5-2(2k-5)

We move all terms to the left:

8k+3(1-2k)-(5-2(2k-5))=0

We add all the numbers together, and all the variables

8k+3(-2k+1)-(5-2(2k-5))=0

We multiply parentheses

8k-6k-(5-2(2k-5))+3=0



We calculate terms in parentheses: -(5-2(2k-5)), so:

5-2(2k-5)

determiningTheFunctionDomain
-2(2k-5)+5

We multiply parentheses

-4k+10+5

We add all the numbers together, and all the variables

-4k+15

Back to the equation:

-(-4k+15)



We add all the numbers together, and all the variables

2k-(-4k+15)+3=0

We get rid of parentheses

2k+4k-15+3=0

We add all the numbers together, and all the variables

6k-12=0

We move all terms containing k to the left, all other terms to the right

6k=12

k=12/6

k=2

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