8k+4(7k-8)-6k=3(6k-12)+64

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Solution for 8k+4(7k-8)-6k=3(6k-12)+64 equation: 



8k+4(7k-8)-6k=3(6k-12)+64

We move all terms to the left:

8k+4(7k-8)-6k-(3(6k-12)+64)=0

We add all the numbers together, and all the variables

2k+4(7k-8)-(3(6k-12)+64)=0

We multiply parentheses

2k+28k-(3(6k-12)+64)-32=0



We calculate terms in parentheses: -(3(6k-12)+64), so:

3(6k-12)+64

We multiply parentheses

18k-36+64

We add all the numbers together, and all the variables

18k+28

Back to the equation:

-(18k+28)



We add all the numbers together, and all the variables

30k-(18k+28)-32=0

We get rid of parentheses

30k-18k-28-32=0

We add all the numbers together, and all the variables

12k-60=0

We move all terms containing k to the left, all other terms to the right

12k=60

k=60/12

k=5

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