8k-3(2k+4)=3(k-6)

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Solution for 8k-3(2k+4)=3(k-6) equation: 



8k-3(2k+4)=3(k-6)

We move all terms to the left:

8k-3(2k+4)-(3(k-6))=0

We multiply parentheses

8k-6k-(3(k-6))-12=0



We calculate terms in parentheses: -(3(k-6)), so:

3(k-6)

We multiply parentheses

3k-18

Back to the equation:

-(3k-18)



We add all the numbers together, and all the variables

2k-(3k-18)-12=0

We get rid of parentheses

2k-3k+18-12=0

We add all the numbers together, and all the variables

-1k+6=0

We move all terms containing k to the left, all other terms to the right

-k=-6

k=-6/-1

k=+6

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