8k-4(k+3)=6-3(k-3,)

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Solution for 8k-4(k+3)=6-3(k-3,) equation: 



8k-4(k+3)=6-3(k-3.)

We move all terms to the left:

8k-4(k+3)-(6-3(k-3.))=0

We add all the numbers together, and all the variables

8k-4(k+3)-(6-3(k-3))=0

We multiply parentheses

8k-4k-(6-3(k-3))-12=0



We calculate terms in parentheses: -(6-3(k-3)), so:

6-3(k-3)

determiningTheFunctionDomain
-3(k-3)+6

We multiply parentheses

-3k+9+6

We add all the numbers together, and all the variables

-3k+15

Back to the equation:

-(-3k+15)



We add all the numbers together, and all the variables

4k-(-3k+15)-12=0

We get rid of parentheses

4k+3k-15-12=0

We add all the numbers together, and all the variables

7k-27=0

We move all terms containing k to the left, all other terms to the right

7k=27

k=27/7

k=3+6/7

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