8k2=98

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Solution for 8k2=98 equation:



8k^2=98
We move all terms to the left:
8k^2-(98)=0
a = 8; b = 0; c = -98;
Δ = b2-4ac
Δ = 02-4·8·(-98)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-56}{2*8}=\frac{-56}{16} =-3+1/2 $
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+56}{2*8}=\frac{56}{16} =3+1/2 $

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