8m(m+4)=16

Solution for 8m(m+4)=16 equation:

8m(m+4)=16

We move all terms to the left:

8m(m+4)-(16)=0

We multiply parentheses

8m^2+32m-16=0

a = 8; b = 32; c = -16;
Δ = b2-4ac
Δ = 322-4·8·(-16)
Δ = 1536
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1536}=\sqrt{256*6}=\sqrt{256}*\sqrt{6}=16\sqrt{6}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-16\sqrt{6}}{2*8}=\frac{-32-16\sqrt{6}}{16}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+16\sqrt{6}}{2*8}=\frac{-32+16\sqrt{6}}{16}
$