8m(m-2)=2m-10

Solution for 8m(m-2)=2m-10 equation:

8m(m-2)=2m-10

We move all terms to the left:

8m(m-2)-(2m-10)=0

We multiply parentheses

8m^2-16m-(2m-10)=0

We get rid of parentheses

8m^2-16m-2m+10=0

We add all the numbers together, and all the variables

8m^2-18m+10=0

a = 8; b = -18; c = +10;
Δ = b2-4ac
Δ = -182-4·8·10
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2}{2*8}=\frac{16}{16}
=1
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2}{2*8}=\frac{20}{16}
=1+1/4
$