8m+2+4m=2(m+1)

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Solution for 8m+2+4m=2(m+1) equation: 



8m+2+4m=2(m+1)

We move all terms to the left:

8m+2+4m-(2(m+1))=0

We add all the numbers together, and all the variables

12m-(2(m+1))+2=0



We calculate terms in parentheses: -(2(m+1)), so:

2(m+1)

We multiply parentheses

2m+2

Back to the equation:

-(2m+2)



We get rid of parentheses

12m-2m-2+2=0

We add all the numbers together, and all the variables

10m=0

m=0/10

m=0

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