8m+4(1-m)=40-2m

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Solution for 8m+4(1-m)=40-2m equation: 



8m+4(1-m)=40-2m

We move all terms to the left:

8m+4(1-m)-(40-2m)=0

We add all the numbers together, and all the variables

8m+4(-1m+1)-(-2m+40)=0

We multiply parentheses

8m-4m-(-2m+40)+4=0

We get rid of parentheses

8m-4m+2m-40+4=0

We add all the numbers together, and all the variables

6m-36=0

We move all terms containing m to the left, all other terms to the right

6m=36

m=36/6

m=6

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